Advertisements
Advertisements
प्रश्न
The pH of 10−5 M KOH solution will be ____________.
विकल्प
9
5
19
none of these
Advertisements
उत्तर
The pH of 10−5 M KOH solution will be 9.
Explanation:
\[\ce{\underset{10^{-5} m}{KOH} -> \underset{10^{-5} m}{K^+} + \underset{10^{-5} m}{OH^-}}\]
[OH–] = 10−5 M
pH = 14 – pOH
pH = 14 – (– log [OH–])
= 14 + log [OH–]
= 14 + log 10−5
= 14 – 5
= 9
APPEARS IN
संबंधित प्रश्न
Assuming complete dissociation, calculate the pH of the following solution:
0.002 M HBr
Calculate the pH of the following solution:
2 g of TlOH dissolved in water to give 2 litre of solution.
The solubility of Sr(OH)2 at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.
Calculate the pH of the resultant mixtures: 10 mL of 0.1M H2SO4 + 10 mL of 0.1M KOH
Derive the relation pH + pOH = 14.
Which complex among the following gives a white precipitate on treatment with an aqueous solution of barium chloride?
Which of the following when dissolved in water results in neutral solution?
pH of a saturated solution of Ca(OH)2 is 9. The Solubility product (Ksp) of Ca(OH)2
Define pOH.
Define pOH.
