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Question
In the given figure, O is the centre of the circle and ∠BDC = 42°. The measure of ∠ACB is
Options
42°
48°
58°
52°
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Solution
48°
Construction: Join A and D.
Since AC is the diameter. So ∠ADC will be 90°.
Therefore,
`angleADB = 90 - angleBDC`
= 90 - 42
`angle ADB = 48°`
∠ACB = ∠ADB = 48° (Angle in the same segment are equal.)
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