Advertisements
Advertisements
Question
In the given figure, O is the centre of the circle and ∠BDC = 42°. The measure of ∠ACB is
Options
42°
48°
58°
52°
Advertisements
Solution
48°
Construction: Join A and D.
Since AC is the diameter. So ∠ADC will be 90°.
Therefore,
`angleADB = 90 - angleBDC`
= 90 - 42
`angle ADB = 48°`
∠ACB = ∠ADB = 48° (Angle in the same segment are equal.)
APPEARS IN
RELATED QUESTIONS
A point P is 13 cm from the centre of the circle. The length of the tangent drawn from P to the circle is 12cm. Find the radius of the circle.
In Fig., if AB = AC, prove that BE = EC
In the given figure, if arc AB = arc CD, then prove that the quadrilateral ABCD is an isosceles– trapezium (O is the centre of the circle).
In the given figure, if chords AB and CD of the circle intersect each other at right angles, then x + y =
Construct a triangle ABC with AB = 4.2 cm, BC = 6 cm and AC = 5cm. Construct the circumcircle of the triangle drawn.
Construct a triangle PQR with QR = 5.5 cm, ∠Q = 60° and angle R = 45°. Construct the circumcircle cif the triangle PQR.
All the radii of a circle are _______________
A point P is 13 cm from the centre of the circle. The length of the tangent drawn from P to the circle is 12cm. Find the radius of the circle.
The circumcentre of the triangle ABC is O. Prove that ∠OBC + ∠BAC = 90º.
AB is a chord of a circle with centre O. AOC is diameter of circle, AT is a tangent at A.
Write answers of the following questions:
- Draw the figure using the given information.
- Find the measures of ∠CAT and ∠ABC with reasons.
- Whether ∠CAT and ∠ABC are congruent? Justify your answer.
