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Question
In the given figure, chords AD and BC intersect each other at right angles at a point P. If ∠DAB = 35°, then
Options
35°
45°
55°
65°
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Solution
55°
`angleBAD = angleBCD = 35°` (Angle in the same segment are equal.)
Also, since the chords ‘AD’ and ‘BC’ intersect perpendicularly we have,
`angleCPD = 90°`
Consider the triangle ΔCPD ,
`angleCPD + anglePDC + anglePCD = 180°`
`anglePDC = 180° - anglePCD - angleCPD`
= 180° - 35° - 90°
= 55°
`anglePDC = angleADC = 55°`
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