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Question
In each of the following, using the remainder theorem, find the remainder when f(x) is divided by g(x) and verify the result by actual division: (1−8)
f(x) = x3 + 4x2 − 3x + 10, g(x) = x + 4
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Solution
Let us denote the given polynomials as
`f(x) = x^3 + 4x^2 - 3x + 10,`
`g(x) = x+ 4`
`⇒ g (x) = x - (-4)`
We have to find the remainder when f(x)is divided by g (x).
By the remainder theorem, when f (x)is divided by g(x)the remainder is
`f(-4) = (-4)^3 +4(-4)^2 - 3(-4) + 10`
` = -64 + 64 + 12 + 10`
`= 22`
Now we will show by actual division

So the remainder by actual division is 22
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