Advertisements
Advertisements
प्रश्न
In each of the following, using the remainder theorem, find the remainder when f(x) is divided by g(x) and verify the result by actual division: (1−8)
f(x) = x3 + 4x2 − 3x + 10, g(x) = x + 4
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = x^3 + 4x^2 - 3x + 10,`
`g(x) = x+ 4`
`⇒ g (x) = x - (-4)`
We have to find the remainder when f(x)is divided by g (x).
By the remainder theorem, when f (x)is divided by g(x)the remainder is
`f(-4) = (-4)^3 +4(-4)^2 - 3(-4) + 10`
` = -64 + 64 + 12 + 10`
`= 22`
Now we will show by actual division

So the remainder by actual division is 22
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Identify constant, linear, quadratic and cubic polynomials from the following polynomials
`p(x)=2x^2-x+4`
If `x = 2` is a root of the polynomial `f(x) = 2x2 – 3x + 7a` find the value of a.
If x − 2 is a factor of the following two polynomials, find the values of a in each case x3 − 2ax2 + ax − 1.
2y3 − 5y2 − 19y + 42
If f(x) = x4 − 2x3 + 3x2 − ax − b when divided by x − 1, the remainder is 6, then find the value of a + b
One factor of x4 + x2 − 20 is x2 + 5. The other factor is
If both x − 2 and \[x - \frac{1}{2}\] are factors of px2 + 5x + r, then
Factorise the following:
a2 + 10a – 600
Factorise:
x3 + x2 – 4x – 4
