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Question
2y3 + y2 − 2y − 1
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Solution
Let f(y) 2y3 + y2 − 2y − 1 be the given polynomial.
Now, putting y = 1we get
`f(1) = 2(1)^3 + (1)^2 - 2(1) - 1 = 2 -2 -1`
` = 3-3 = 0`
Now,
`f(y) = 2y^2 (y - 1) + 3y(y-1)+1(y-1)`
` = (y -1){2y^2 + 3y +1}`
` = (y - 1){2y^2 + 2y + y +1}`
` = (y-1)(2y +1)(y +1)`
Hence (y -1),(y+1) and (2y +1)are the factors of polynomial f(y).
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