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Question
x4 − 2x3 − 7x2 + 8x + 12
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Solution
Let `f(x) = x^4 - 2x^3 - 7x^2 + 8x + 12` be the given polynomial.
Now, putting x = -1we get
`f (-1) = (-1)^4 -2 (-1)^3 - 7 ( -1)^2 + 8 (-1)+12`
` = 1 + 2 - 7 - 8 _ 12 = -15 + 15`
` = 0`
Therefore, (x + 1)is a factor of polynomial f(x).
Now,
\[f(x) = x^4 - 3 x^3 + x^3 - 3 x^2 - 4 x^2 + 12x - 4x + 12\]
`f(x) = x^3 (x+1) -3x^2 (x +1) - 4x(x+1) + 12 (x +1)`
` = (x +1){x^3 -3x^2 - 4x + 12}`
`=(x+1)g(x) ......... (1)`
Where `g(x)=x^3 -3x^2 - 4x + 12`
Putting x = 2,we get
`g(2) = (2)^3 -3(2)^2 - 4 (2) + 12`
`8 -12 -8 +12 = 20 -20`
` = 0`
Therefore, (x -2)is the factor of g(x).
Now,
\[g(x) = x^3 - 2 x^2 - x^2 - 6x + 2x + 12\]
`g(x) = x^2 (x -2) -x (x -2) -6(x - 2)`
` = (x -2){x^2 -x -6}`
` = (x-2){x^2 - 3x +2x -6}`
` = (x-2)(x+2) (x-3) ......... (2)`
From equation (i) and (ii), we get
`f(x) = (x+1)(x -2)(x+2)(x-3)`
Hence (x +1),(x -2),(x +2) and (x-3) are the factors of polynomial f(x).
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