Advertisements
Advertisements
Question
In a photographic process, the developing time of prints may be looked upon as a random variable having the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second. Find the probability that it will take less than 16.35 seconds to develop prints
Advertisements
Solution
Let x be the random variable have long the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second
µ = 16,28 and σ = 0.12
The standard normal variate
z = `(x - mu)/sigma = (x - 16.28)/0.12` = 1
P(Less than 16.35 seconds) = P(x < 16.35)
When x = 16.35
z = `(16.35 - 16.28)/0.12 = 0.17/0.12` = 0.583
P(X < 16.35) = P(Z < 0.583)
= P(`-oo` < z < 0) + P(0 < z < 0.583)
= 0.5 + 0.2190
= 0.7190
APPEARS IN
RELATED QUESTIONS
Out of 750 families with 4 children each, how many families would be expected to have atmost 2 girls
Forty percent of business travellers carry a laptop. In a sample of 15 business travelers, what is the probability that 3 will have a laptop?
A car hiring firm has two cars. The demand for cars on each day is distributed as a Posison variate, with mean 1.5. Calculate the proportion of days on which some demand is refused
The average number of phone calls per minute into the switchboard of a company between 10.00 am and 2.30 pm is 2.5. Find the probability that during one particular minute there will be no phone at all
In a distribution 30% of the items are under 50 and 10% are over 86. Find the mean and standard deviation of the distribution
Choose the correct alternative:
Normal distribution was invented by
Choose the correct alternative:
If the area to the left of a value of z (z has a standard normal distribution) is 0.0793, what is the value of z?
If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calculate the probability that there will not be more than one failure during a particular week
Vehicles pass through a junction on a busy road at an average rate of 300 per hour. Find the probability that none passes in a given minute
X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(X < 40)
