Advertisements
Advertisements
प्रश्न
In a photographic process, the developing time of prints may be looked upon as a random variable having the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second. Find the probability that it will take less than 16.35 seconds to develop prints
Advertisements
उत्तर
Let x be the random variable have long the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second
µ = 16,28 and σ = 0.12
The standard normal variate
z = `(x - mu)/sigma = (x - 16.28)/0.12` = 1
P(Less than 16.35 seconds) = P(x < 16.35)
When x = 16.35
z = `(16.35 - 16.28)/0.12 = 0.17/0.12` = 0.583
P(X < 16.35) = P(Z < 0.583)
= P(`-oo` < z < 0) + P(0 < z < 0.583)
= 0.5 + 0.2190
= 0.7190
APPEARS IN
संबंधित प्रश्न
Mention the properties of binomial distribution.
In a particular university 40% of the students are having newspaper reading habit. Nine university students are selected to find their views on reading habit. Find the probability that atleast two-third have newspaper reading habit
If 18% of the bolts produced by a machine are defective, determine the probability that out of the 4 bolts chosen at random none will be defective
Forty percent of business travellers carry a laptop. In a sample of 15 business travelers, what is the probability that atleast three of the travelers have a laptop?
In a test on 2,000 electric bulbs, it was found that bulbs of a particular make, was normally distributed with an average life of 2,040 hours and standard deviation of 60 hours. Estimate the number of bulbs likely to burn for more 1,920 hours but less than 2,100 hours
If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calculate the probability that there will not be more than one failure during a particular week
Vehicles pass through a junction on a busy road at an average rate of 300 per hour. Find the probability that none passes in a given minute
The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $20,000. What percent of people earn less than $40,000?
X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(X < 40)
X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(X > 21)
