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Question
If 18% of the bolts produced by a machine are defective, determine the probability that out of the 4 bolts chosen at random none will be defective
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Solution
P(none will be defective) P(X = 0)
= 4C0(0.18)°(0.82)4-0
= (1)(1)(0.45212176)
P(X = 0) = 0.45212
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