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Question
In a common-base connection, a certain transistor has an emitter current of 10mA and a collector current of 9.8 mA. Calculate the value of the base current.
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Solution
Data: IE = 10 mA, lC = 9.8 mA
IE = IB + IC
Therefore, the base current,
IB = IE - IC = 10 - 9.8 = 0.2 mA
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