Question

If `x = (-1)/2` is a solution of the quadratic equation 3x² + 2kx – 3 = 0, find the value of k.

Answer 1

It is given that `x = (-1)/2` is a solution of the quadratic equation 3x² + 2kx – 3 = 0 

∴ `3 xx ((-1)/2)^2 + 2k xx ((-1)/2) - 3 = 0` 

⇒ `3/4 - k - 3 = 0` 

⇒ `k = (3 - 12)/4`

 ⇒ `k = (-9)/4` 

Hence, the value of k is `(-9)/4`.