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प्रश्न
If `x = (-1)/2` is a solution of the quadratic equation 3x2 + 2kx – 3 = 0, find the value of k.
योग
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उत्तर
It is given that `x = (-1)/2` is a solution of the quadratic equation 3x2 + 2kx – 3 = 0
∴ `3 xx ((-1)/2)^2 + 2k xx ((-1)/2) - 3 = 0`
⇒ `3/4 - k - 3 = 0`
⇒ `k = (3 - 12)/4`
⇒ `k = (-9)/4`
Hence, the value of k is `(-9)/4`.
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