Question

If the prime factorization of a natural number n is 2³ × 3² × 5² × 7, write the number of consecutive zeros in n.

Answer 1

Since, it is given that 

`n= 2^3xx3^2xx5^2xx7`

`n= 8xx9xx25xx7`

`n=(7xx9xx2)xx(4xx25)`

`n=(7xx9xx2)xx100`

`n=(7xx9xx2)xx100`

`n= 12600`

Hence the number of consecutive zeroes are 2.