Question

If p₁^x₁ × p₂^x₂ × p₃^x₃ × p₄^x₄ = 113400 where p₁, p₂, p₃, p₄ are primes in ascending order and x₁, x₂, x₃, x₄, are integers, find the value of p₁, p₂, p₃, p₄ and x₁, x₂, x₃, x₄

Answer 1

Given 113400 = p₁^x₁ × p₂^x₂ × p₃^x₃ × p₄^x₄

Using tree method factorise 113400

113400 = 23 × 34 × 52 × 7

compare with

113400 = p₁^x₁ × p₂^x₂ × p₃^x₃ × p₄^x₄

P₁ = 2, x₁ = 3

P₂ = 3, x₂ = 4

P₃ = 5, x₃ = 2

P₄ = 7, x₄ = 1