English

The Hcf of Two Numbers is 145 and Their Lcm is 2175. If One Number is 725, Find the Other.

Advertisements
Advertisements

Question

The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, find the other.

Numerical
Advertisements

Solution

GIVEN: LCM and HCF of two numbers are 2175 and 145 respectively. If one number is 725

TO FIND: Other number 

We know that,

L.C.M x H.C.M = First  Numbers x Second Numbers 

2175 x 145 = 725 x Second Numbers 

Second Numbers = `(2175 xx145)/725`

shaalaa.com
  Is there an error in this question or solution?

RELATED QUESTIONS

Consider the number 6n where n is a natural number. Check whether there is any value of n ∈ N for which 6n is divisible by 7.


Given that HCF (306, 657) = 9, find LCM (306, 657).


Check whether 6n can end with the digit 0 for any natural number n.


Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.


Determine the prime factorisation of each of the following positive integer:

45470971


If the prime factorization of a natural number n is 23 ✕ 32 ✕ 52 ✕ 7, write the number of consecutive zeros in n.


Express the number as a product of its prime factor:

5005


Find the LCM and HCF of the following integers by applying the prime factorisation method.

8, 9 and 25


For some integer p, every odd integer is of the form ______.


If two positive integers A and B can be expressed as A = xy3 and B = x4y2z; x, y being prime numbers then HCF (A, B) is ______.


The largest number which divides 60 and 75, leaving remainders 8 and 10 respectively, is ______.


The number in the form of 4p + 3, where p is a whole number, will always be ______.


For some integer q, every odd integer is of the form ______.


If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is ______.


If two positive integers p and q can be expressed as p = ab2 and q = a3b; a, b being prime numbers, then LCM (p, q) is ______.


The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is ______.


Show that 12n cannot end with the digit 0 or 5 for any natural number n.


(HCF × LCM) for the numbers 70 and 40 is ______.


(HCF × LCM) for the numbers 30 and 70 is ______.


The HCF of the smallest 2-digit number and the smallest composite number is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×