Advertisements
Advertisements
Question
If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22 and 37 respectively. Find the quotient in each case.
Advertisements
Solution
\[\text{ The sum of }(985 + 859 + 598)\text{ when divided by }: \]
\[(i) 111\]
\[\text{ Quotient }= (9 + 8 + 5) = 22\]
\[(ii) 22, i . e, (9 + 8 + 5)\]
\[\text{ Quotient }= 111\]
\[(iii) 37 ( = \frac{111}{3})\]
\[\text{ Quotient }= 3(9 + 8 + 5) = 66\]
APPEARS IN
RELATED QUESTIONS
Without performing actual addition and division write the quotient when the sum of 69 and 96 is divided by
(i) 11
(ii) 15
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and ______.
If
then B = ______.
If AB × 4 = 192, then A + B = 7.
A five-digit number AABAA is divisible by 33. Write all the numbers of this form.
1y3y6 is divisible by 11. Find the value of y.
756x is a multiple of 11, find the value of x.
If 148101B095 is divisible by 33, find the value of B.
Fill in the blank space in the same way.

