Advertisements
Advertisements
प्रश्न
If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22 and 37 respectively. Find the quotient in each case.
Advertisements
उत्तर
\[\text{ The sum of }(985 + 859 + 598)\text{ when divided by }: \]
\[(i) 111\]
\[\text{ Quotient }= (9 + 8 + 5) = 22\]
\[(ii) 22, i . e, (9 + 8 + 5)\]
\[\text{ Quotient }= 111\]
\[(iii) 37 ( = \frac{111}{3})\]
\[\text{ Quotient }= 3(9 + 8 + 5) = 66\]
APPEARS IN
संबंधित प्रश्न
Given an example of a number which is divisible by 4 but not by 8.
Given an example of a number which is divisible by both 4 and 8 but not by 32.
Do you remember magic triangles? Come now, let s make some magic squares.
- Fill this square using all the numbers from 46 to 54.
Rule: The total of each line is 150.
Use the same rule to fill the hexagons below.

Now you also make your own magic hexagons.
Now you try and change these numbers into special numbers —
28
If A3 + 8B = 150, then the value of A + B is ______.
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
If B × B = AB, then either A = 2, B = 5 or A = ______, B = ______.
A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
