Advertisements
Advertisements
प्रश्न
If 56 × 32y is divisible by 18, find the least value of y.
Advertisements
उत्तर
It is given that, the number 56 × 32y is divisible by 18.
Then, it is also divisible by each factor of 18.
Thus, it is divisible by 2 as well as 3.
Now, the number is divisible by -2, its unit’s digit must be an even number that is 0, 2, 4, 6, Therefore, the least value of y is 0.
Again, the number is divisible by 3 also, sum of its digits is a multiple of 3. i.e. 5 + 6 + x + 3 + 2 + y is a multiple of 3
⇒ 16 + x + y = 0, 3, 6, 9,...
⇒ 16 + x = 18
⇒ x = 2, which is the least value of x.
APPEARS IN
संबंधित प्रश्न
If \[\overline{{3x2}}\] is a multiple of 11, where x is a digit, what is the value of x?
Given an example of a number which is divisible by 4 but not by 8.
Which of the following statement is true?
If a number is divisible by both 9 and 10, it must be divisible by 90.
Use the same rule to fill the hexagons below.
Now you also make your own magic hexagons.
If 
then B = ______.
If the digit 1 is placed after a 2-digit number whose tens is t and ones digit is u, the new number is ______.
If AB × 4 = 192, then A + B = 7.
Find the value of k where 31k2 is divisible by 6.
If 148101B095 is divisible by 33, find the value of B.
Fill in the blank space in the same way.
