Advertisements
Advertisements
प्रश्न
If 56 × 32y is divisible by 18, find the least value of y.
Advertisements
उत्तर
It is given that, the number 56 × 32y is divisible by 18.
Then, it is also divisible by each factor of 18.
Thus, it is divisible by 2 as well as 3.
Now, the number is divisible by -2, its unit’s digit must be an even number that is 0, 2, 4, 6, Therefore, the least value of y is 0.
Again, the number is divisible by 3 also, sum of its digits is a multiple of 3. i.e. 5 + 6 + x + 3 + 2 + y is a multiple of 3
⇒ 16 + x + y = 0, 3, 6, 9,...
⇒ 16 + x = 18
⇒ x = 2, which is the least value of x.
APPEARS IN
संबंधित प्रश्न
Which of the following statement is true?
If a number exactly divides the sum of two numbers, it must exactly divide the numbers separately.
Which of the following statement is true?
If a number divides three numbers exactly, it must divide their sum exactly.
Look at the patterns of numbers in hexagons.
Each side has 2 circles and 1 box.
- Look at the number 65 in the box. Which are the circles next to it?
- Can you see how the rule works?
Now, look at this —
Check if it is true or not.
The difference of a two-digit number and the number obtained by reversing its digits is always divisible by ______.
If 
then B = ______.
If A × 3 = 1A, then A = ______.
Number 7N + 1 will leave remainder 1 when divided by 7.
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
Fill in the blank space in the same way.
