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प्रश्न
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
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उत्तर
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by 11.
Explanation:
Let ab be any two-digit number, then the number obtained by reversing its digits is ba.
Now, ab + ba = (10a + b) + (10b + a)
= 11a + 11b
= 11(a + b)
Hence, ab + ba is always divisible by 11 and (a + b).
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संबंधित प्रश्न
Look at the patterns of numbers in hexagons.
Each side has 2 circles and 1 box.
- Look at the number 65 in the box. Which are the circles next to it?
- Can you see how the rule works?
Use the same rule to fill the hexagons below.
Now you also make your own magic hexagons.
Now, look at this —
Check if it is true or not.
If A3 + 8B = 150, then the value of A + B is ______.
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If 
then B = ______.
If the digit 1 is placed after a 2-digit number whose tens is t and ones digit is u, the new number is ______.
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A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.
If 56 × 32y is divisible by 18, find the least value of y.
