Advertisements
Advertisements
प्रश्न
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
Advertisements
उत्तर
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by 11.
Explanation:
Let ab be any two-digit number, then the number obtained by reversing its digits is ba.
Now, ab + ba = (10a + b) + (10b + a)
= 11a + 11b
= 11(a + b)
Hence, ab + ba is always divisible by 11 and (a + b).
APPEARS IN
संबंधित प्रश्न
If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22 and 37 respectively. Find the quotient in each case.
Which of the following statement is true?
If a number is divisible by 8, it must be divisible by 4.
Which of the following statement is true?
If a number exactly divides the sum of two numbers, it must exactly divide the numbers separately.
Which of the following statement is true?
If a number divides three numbers exactly, it must divide their sum exactly.
Do you remember magic triangles? Come now, let s make some magic squares.
- Fill this square using all the numbers from 46 to 54.
Rule: The total of each line is 150.
Look at the patterns of numbers in hexagons.
Each side has 2 circles and 1 box.
- Look at the number 65 in the box. Which are the circles next to it?
- Can you see how the rule works?
A four-digit number abcd is divisible by 4 if ab is divisible by 4.
If N ÷ 5 leaves remainder 3 and N ÷ 2 leaves remainder 0, then N ÷ 10 leaves remainder 4.
1y3y6 is divisible by 11. Find the value of y.
Fill in the blank space in the same way.
