Advertisements
Advertisements
प्रश्न
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
Advertisements
उत्तर
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by 11.
Explanation:
Let ab be any two-digit number, then the number obtained by reversing its digits is ba.
Now, ab + ba = (10a + b) + (10b + a)
= 11a + 11b
= 11(a + b)
Hence, ab + ba is always divisible by 11 and (a + b).
APPEARS IN
संबंधित प्रश्न
Find the quotient when the difference of 985 and 958 is divided by 9.
Given an example of a number which is divisible by both 4 and 8 but not by 32.
Which of the following statement is true?
A number is divisible by 18, if it is divisible by both 3 and 6.
Now you try and change these numbers into special numbers —
28
If
then B = ______.
Number 7N + 1 will leave remainder 1 when divided by 7.
If AB × 4 = 192, then A + B = 7.
A five-digit number AABAA is divisible by 33. Write all the numbers of this form.
Fill in the blank space in the same way.

Fill in the blank space in the same way.

