Advertisements
Advertisements
प्रश्न
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
पर्याय
True
False
Advertisements
उत्तर
This statement is True.
Explanation:
AB
We have, + 7C
102
Here, B + C is either 2 or a two-digit number whose one’s digit is 2.
If B = C = 1, lf 8 = 5, C = 7, A = 2 and A + B + C = 2 + 5 + 7 = 14
APPEARS IN
संबंधित प्रश्न
Without performing actual computations, find the quotient when 94 − 49 is divided by
(i) 9
(ii) 5
Given an example of a number which is divisible by 2 but not by 4.
Given an example of a number which is divisible by 4 but not by 8.
Look at the patterns of numbers in hexagons.
Each side has 2 circles and 1 box.


- Look at the number 65 in the box. Which are the circles next to it?
- Can you see how the rule works?
Now you try and change these numbers into special numbers —
28
A number is divisible by 11 if the differences between the sum of digits at its odd places and that of digits at the even places is either 0 or divisible by ______.
If A × 3 = 1A, then A = ______.
If 148101B095 is divisible by 33, find the value of B.
Fill in the blank space in the same way.

Fill in the blank space in the same way.

