Advertisements
Advertisements
प्रश्न
The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and ______.
Advertisements
उत्तर
The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and 11.
Explanation:
Let abc be a three-digit number, then we have
abc – cba = (100a + 10b + c) – (100c + 10b + a)
= (100a – a) + (c – 100c)
= 99a – 99c
= 99(a – c)
= 9 × 11 × (a – c)
Hence, abc – cba is always divisible by 9, 11 and (a – c).
APPEARS IN
संबंधित प्रश्न
Without performing actual addition and division write the quotient when the sum of 69 and 96 is divided by
(i) 11
(ii) 15
If \[\overline{{3x2}}\] is a multiple of 11, where x is a digit, what is the value of x?
Given an example of a number which is divisible by 4 but not by 8.
Which of the following statement is true?
If a number is divisible by both 9 and 10, it must be divisible by 90.
Use the same rule to fill the hexagons below.
Now you also make your own magic hexagons.
Fill in the blank space in the same way.
Now you try and change these numbers into special numbers —
132
If A3 + 8B = 150, then the value of A + B is ______.
If 6A × B = A 8 B, then the value of A – B is ______.
If a number a is divisible by b, then it must be divisible by each factor of b.
