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Question
Find the value of k where 31k2 is divisible by 6.
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Solution
Given, 31k2 is divisible by 6.
Then, it is also divisible by 2 and 3 both.
Now, 31k2 is divisible by 3, sum of its digits is a multiple of 3.
i.e. 3 + 1 + k + 2 = 0, 3, 6, 9, 12,...
⇒ k + 6 = 0, 3, 6, 9, 12
⇒ k = 0 or 3, 6, 9
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