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If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164? - Mathematics

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Question

If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164?

Options

  •  26th

  •  27th

  •  28th

  • none of these.

MCQ
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Solution

Here, the sum of first n terms is given by the expression,

Sn = 3n2 + 5n

We need to find which term of the A.P. is 164.

Let us take 164 as the nth term

So we know that the nthterm of an A.P. is given by,

an = Sn - Sn-1

So,

164 = Sn - Sn-1

164 = 3n2 + 5n - [3(n-1)2 +5(n-1) ] 

Using the property,

( a - b)2 = a2 + b2 - 2ab

We get,

164 = 3n2 + 5n - [3(n2 + 1 - 2n) + 5 ( n-1)] 

164 = 3n2 + 5n - [3n2 + 3 - 6n + 5n - 5]

164 = 3n2 + 5n -(3n2 - n - 2)

164 = 3n2 + 5n - 3n2 + n + 2

164 = 6n + 2

Further solving for n, we get

6n = 164 - 2  

  `n = 162/6`

    n = 27

Therefore,  164 is the 27th term of the given A.P. 

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Chapter 5: Arithmetic Progression - Exercise 5.8 [Page 57]

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RD Sharma Mathematics [English] Class 10
Chapter 5 Arithmetic Progression
Exercise 5.8 | Q 5 | Page 57

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