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Question
In the month of April to June 2022, the exports of passenger cars from India increased by 26% in the corresponding quarter of 2021-22, as per a report. A car manufacturing company planned to produce 1800 cars in 4th year and 2600 cars in 8th year. Assuming that the production increases uniformly by a fixed number every year.![]() |
Based on the above information answer the following questions.
- Find the production in the 1st year
- Find the production in the 12th year.
- Find the total production in first 10 years.
[OR]
In how many years will the total production reach 31200 cars?
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Solution
I. Since the production increases uniformly by a fixed number every year, the number of cars manufactured in 1st, 2nd, 3rd, ...., years will form an AP.
So, a + 3d = 1800 and a + 7d = 2600
So d = 200 and a = 1200
II. t12 = a + 11d
⇒ t30 = 1200 + 11 × 200
⇒ t12 = 3400
III. Sn = `n/2 [2a + (n - 1)d]`
⇒ S10 = `10/2 [2 xx 1200 + (10 - 1) 200]`
⇒ S10 = `13/2 [2 xx 1200 + 9 xx 200]`
⇒ S10 = 5 × [2400 + 1800]
⇒ S10 = 5 × 4200
⇒ S10 = 21000
[OR]
Let in n years the production will reach to 31200.
Sn = `n/2 [2a + (n - 1)d]` = 31200
⇒ `n/2 [2 xx 1200 + (n - 1)200]` = 31200
⇒ n[12 + (n – 1)] = 312
⇒ n2 + 11n – 312 = 0
⇒ n2 + 24n – 13n – 312 = 0
⇒ (n + 24) (n – 13) = 0
⇒ n = 13 or – 24
As n can’t be negative.
So n = 13

