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If α + β − γ = π and Sin2 α +Sin2 β − Sin2 γ = λ Sin α Sin β Cos γ, Then Write the Value of λ.

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Question

If α + β − γ = π and sin2 α +sin2 β − sin2 γ = λ sin α sin β cos γ, then write the value of λ. 

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Solution

\[\text{ Given }:\]

\[\gamma = - \left[ \pi - (\alpha + \beta) \right]\]

\[\text{ Also }, \]

\[\lambda = \frac{\sin^2 \alpha + \sin^2 \beta - \sin^2 \left[ - (\pi - (\alpha + \beta) \right]}{\sin\alpha \sin\beta \cos( - (\pi - (\alpha + \beta))} \]

\[ = \frac{\sin^2 \alpha + \sin^2 \beta - (\sin(\alpha + \beta) )^2}{- (\sin\alpha \sin\beta\cos(\alpha + \beta))} \left[ \sin \left( \pi - \theta \right) = \sin \theta and \cos\left( \pi - \theta \right) = - \cos \theta \right]\]

\[ = \frac{\sin^2 \alpha + \sin^2 \beta - \sin^2 \alpha \cos^2 \beta - \cos^2 \alpha \sin^2 \beta - 2\sin\alpha \sin\beta \cos\alpha \cos\beta}{- (\sin\alpha \sin\beta \cos\alpha \cos\beta - \sin^2 \alpha \sin^2 \beta)}\]

\[ = \frac{\sin^2 \alpha(1 - \cos^2 \beta) + \sin^2 \beta(1 - \cos^2 \alpha) - 2\sin\alpha \sin\beta \cos\alpha \cos\beta}{\sin^2 \alpha \sin^2 \beta - \sin\alpha \sin\beta \cos\alpha \cos\beta}\]

\[ = \frac{2 \sin^2 \alpha \sin^2 \beta - 2\sin\alpha \sin\beta \cos\alpha \cos\beta}{\sin^2 \alpha \sin^2 \beta - \sin\alpha \sin\beta \cos\alpha \cos\beta}\]

\[ = 2\]

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Chapter 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.3 [Page 26]

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R.D. Sharma Mathematics [English] Class 11
Chapter 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.3 | Q 1 | Page 26

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