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Question
If `secθ = 25/7 ` then find tanθ.
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Solution
`1 + tan^2θ = sec^2θ`
`1 + tan^2θ =(25/7)^2`
`∴ tan^2θ =625/49- 1`
`∴ tan^2θ =(625-49)/49`
`∴ tan^2θ =576/49`
`∴ tanθ =24/7`
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