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Question
If P01(L) = 90 and P01(P) = 40, find P01(D – B) and P01(F).
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Solution
Given, P01(L) = 90 and P01(P) = 40
`"P"_01 ("D - B") = ("P"_01("L") + "P"_01 ("P"))/2`
`= (90 + 40)/2 = 130/2 = 65`
`"P"_01("F") = sqrt("P"_01 ("L") xx "P"_01 ("P"))`
`= sqrt(90 xx 40) = sqrt3600 = 60`
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