English

If Cos X = − 1 2 and 0 < X < 2\Pi, Then the Solutions Are

Advertisements
Advertisements

Question

If \[\cos x = - \frac{1}{2}\] and 0 < x < 2\pi, then the solutions are

Options

  • \[x = \frac{\pi}{3}, \frac{4\pi}{3}\]

     

  • \[x = \frac{2\pi}{3}, \frac{4\pi}{3}\]

     

  • \[x = \frac{2\pi}{3}, \frac{7\pi}{6}\]

     

  • \[\theta = \frac{2\pi}{3}, \frac{5\pi}{3}\]

     

MCQ
Sum
Advertisements

Solution

\[x = \frac{2\pi}{3}, \frac{4\pi}{3}\]
Given equation:
\[\cos x = - \frac{1}{2}\]
\[ \Rightarrow \cos x = \cos \frac{2\pi}{3}\]
\[ \Rightarrow x = \frac{2\pi}{3}\]
Or,
\[\cos x = \cos \frac{4\pi}{3}\]
\[ \Rightarrow x = \frac{4\pi}{3}\]
So, both 
\[\frac{2\pi}{3} \text{ and }\frac{4\pi}{3}\] lie in
\[0 < x < 2\pi\].
shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Trigonometric equations - Exercise 11.3 [Page 28]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 11 Trigonometric equations
Exercise 11.3 | Q 20 | Page 28

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the general solution of the equation sin 2x + cos x = 0


If \[\tan x = \frac{b}{a}\] , then find the values of \[\sqrt{\frac{a + b}{a - b}} + \sqrt{\frac{a - b}{a + b}}\].


If \[a = \sec x - \tan x \text{ and }b = cosec x + \cot x\], then shown that  \[ab + a - b + 1 = 0\]


If \[T_n = \sin^n x + \cos^n x\], prove that  \[2 T_6 - 3 T_4 + 1 = 0\]


In a ∆ABC, prove that:

\[\cos\left( \frac{A + B}{2} \right) = \sin\frac{C}{2}\]

 


Find x from the following equations:
\[x \cot\left( \frac{\pi}{2} + \theta \right) + \tan\left( \frac{\pi}{2} + \theta \right)\sin \theta + cosec\left( \frac{\pi}{2} + \theta \right) = 0\]


Prove that:

\[\tan\frac{5\pi}{4}\cot\frac{9\pi}{4} + \tan\frac{17\pi}{4}\cot\frac{15\pi}{4} = 0\]

 


If sec \[x = x + \frac{1}{4x}\], then sec x + tan x = 

 

\[\sqrt{\frac{1 + \cos x}{1 - \cos x}}\] is equal to

 


If \[\frac{3\pi}{4} < \alpha < \pi, \text{ then }\sqrt{2\cot \alpha + \frac{1}{\sin^2 \alpha}}\] is equal to


If x sin 45° cos2 60° = \[\frac{\tan^2 60^\circ cosec30^\circ}{\sec45^\circ \cot^{2^\circ} 30^\circ}\], then x =

 

The value of \[\tan1^\circ \tan2^\circ \tan3^\circ . . . \tan89^\circ\] is

 

Which of the following is correct?


Find the general solution of the following equation:

\[\tan 3x = \cot x\]

Find the general solution of the following equation:

\[\tan 2x \tan x = 1\]

Find the general solution of the following equation:

\[\sin x = \tan x\]

Solve the following equation:

\[2 \cos^2 x - 5 \cos x + 2 = 0\]

Solve the following equation:

\[3 \cos^2 x - 2\sqrt{3} \sin x \cos x - 3 \sin^2 x = 0\]

Solve the following equation:

\[\cos x + \sin x = \cos 2x + \sin 2x\]

Solve the following equation:
\[\sin x + \cos x = \sqrt{2}\]


Solve the following equation:

\[\sin x + \cos x = 1\]

Solve the following equation:
\[2 \sin^2 x = 3\cos x, 0 \leq x \leq 2\pi\]


Write the values of x in [0, π] for which \[\sin 2x, \frac{1}{2}\]

 and cos 2x are in A.P.


If a is any real number, the number of roots of \[\cot x - \tan x = a\] in the first quadrant is (are).


The general value of x satisfying the equation
\[\sqrt{3} \sin x + \cos x = \sqrt{3}\]


A value of x satisfying \[\cos x + \sqrt{3} \sin x = 2\] is

 

General solution of \[\tan 5 x = \cot 2 x\] is


The solution of the equation \[\cos^2 x + \sin x + 1 = 0\] lies in the interval


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

sin4x = sin2x


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 cos2x + 1 = – 3 cos x


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 sin2x + 1 = 3 sin x


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

cos 2x = 1 − 3 sin x


Solve the following equations:
sin 5x − sin x = cos 3


Solve the following equations:
2 cos2θ + 3 sin θ – 3 = θ


Solve the following equations:
cos θ + cos 3θ = 2 cos 2θ


Solve the following equations:
sin 2θ – cos 2θ – sin θ + cos θ = θ


If a cosθ + b sinθ = m and a sinθ - b cosθ = n, then show that a2 + b2 = m2 + n2 


Find the general solution of the equation sinx – 3sin2x + sin3x = cosx – 3cos2x + cos3x


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×