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General Solution of Tan 5 X = Cot 2 X is

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Question

General solution of \[\tan 5 x = \cot 2 x\] is

Options

  • \[\frac{n \pi}{7} + \frac{\pi}{2}, n \in Z\]

  • \[x = \frac{n \pi}{7} + \frac{\pi}{3}, n \in Z\]

     

  • \[x = \frac{n \pi}{7} + \frac{\pi}{14}, n \in Z\]

     

  • \[x = \frac{n \pi}{7} - \frac{\pi}{14}, n \in Z\]

     

MCQ
Sum
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Solution

\[x = \frac{n \pi}{7} - \frac{\pi}{14}, n \in Z\]
Given:
\[\tan5x = \cot2x\]
\[ \Rightarrow \tan5x = \tan \left( \frac{\pi}{2} - 2x \right)\]
\[ \Rightarrow 5x = n\pi + \frac{\pi}{2} - 2x\]
\[ \Rightarrow 7x = n\pi + \frac{\pi}{2}\]
\[ \Rightarrow x = \frac{n\pi}{7} + \frac{\pi}{14} , n \in Z\]
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Chapter 11: Trigonometric equations - Exercise 11.3 [Page 28]

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R.D. Sharma Mathematics [English] Class 11
Chapter 11 Trigonometric equations
Exercise 11.3 | Q 18 | Page 28

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