English

If sin θ and cos θ are the roots of the equation ax2 – bx + c = 0, then a, b and c satisfy the relation ______.

Advertisements
Advertisements

Question

If sin θ and cos θ are the roots of the equation ax2 – bx + c = 0, then a, b and c satisfy the relation ______.

Options

  • a2 + b2 + 2ac = 0

  • a2 – b2 + 2ac = 0

  • a2 + c2 + 2ab = 0

  • a2 – b2 – 2ac = 0

MCQ
Fill in the Blanks
Advertisements

Solution

If sin θ and cos θ are the roots of the equation ax2 – bx + c = 0, then a, b and c satisfy the relation a2 – b2 + 2ac = 0.

Explanation:

Given that sin θ and cos θ are the roots of the equation ax2 – bx + c = 0

So sin θ + cos θ = `b/a` and sin θ cos θ = `c/a`

Using the identity (sinθ + cos θ)2 = sin2θ + cos2θ + 2 sin θ cos θ

We have `b^2/a^2 = 1 + (2c)/a`

or a2 – b2 + 2ac = 0

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Trigonometric Functions - Solved Examples [Page 48]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 3 Trigonometric Functions
Solved Examples | Q 16 | Page 48

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the general solution of the equation sin 2x + cos x = 0


Find the general solution for each of the following equations sec2 2x = 1– tan 2x


Find the general solution of the equation  sin x + sin 3x + sin 5x = 0


If \[cosec x - \sin x = a^3 , \sec x - \cos x = b^3\], then prove that \[a^2 b^2 \left( a^2 + b^2 \right) = 1\]


If \[\cot x \left( 1 + \sin x \right) = 4 m \text{ and }\cot x \left( 1 - \sin x \right) = 4 n,\] \[\left( m^2 + n^2 \right)^2 = mn\]


If \[T_n = \sin^n x + \cos^n x\], prove that \[\frac{T_3 - T_5}{T_1} = \frac{T_5 - T_7}{T_3}\]

 


If \[T_n = \sin^n x + \cos^n x\], prove that \[6 T_{10} - 15 T_8 + 10 T_6 - 1 = 0\]


Prove that:
\[\sin^2 \frac{\pi}{18} + \sin^2 \frac{\pi}{9} + \sin^2 \frac{7\pi}{18} + \sin^2 \frac{4\pi}{9} = 2\]

 

In a ∆ABC, prove that:

\[\cos\left( \frac{A + B}{2} \right) = \sin\frac{C}{2}\]

 


Find x from the following equations:
\[cosec\left( \frac{\pi}{2} + \theta \right) + x \cos \theta \cot\left( \frac{\pi}{2} + \theta \right) = \sin\left( \frac{\pi}{2} + \theta \right)\]


\[\sqrt{\frac{1 + \cos x}{1 - \cos x}}\] is equal to

 


Which of the following is correct?


Find the general solution of the following equation:

\[cosec x = - \sqrt{2}\]

Find the general solution of the following equation:

\[\sqrt{3} \sec x = 2\]

Find the general solution of the following equation:

\[\tan 3x = \cot x\]

Find the general solution of the following equation:

\[\tan px = \cot qx\]

 


Find the general solution of the following equation:

\[\sin x = \tan x\]

Solve the following equation:

\[4 \sin^2 x - 8 \cos x + 1 = 0\]

Solve the following equation:

\[\tan^2 x + \left( 1 - \sqrt{3} \right) \tan x - \sqrt{3} = 0\]

Solve the following equation:

\[\sin x + \sin 5x = \sin 3x\]

Solve the following equation:

\[\sin x + \sin 2x + \sin 3 = 0\]

Solve the following equation:

\[\sin 2x - \sin 4x + \sin 6x = 0\]

Solve the following equation:

\[\tan 3x + \tan x = 2\tan 2x\]

Solve the following equation:

`cosec  x = 1 + cot x`


Solve the following equation:
\[\sec x\cos5x + 1 = 0, 0 < x < \frac{\pi}{2}\]


Solve the following equation:
\[2^{\sin^2 x} + 2^{\cos^2 x} = 2\sqrt{2}\]


Write the general solutions of tan2 2x = 1.

 

Write the number of points of intersection of the curves

\[2y = 1\] and \[y = \cos x, 0 \leq x \leq 2\pi\].
 

The smallest value of x satisfying the equation

\[\sqrt{3} \left( \cot x + \tan x \right) = 4\] is 

The general solution of the equation \[7 \cos^2 x + 3 \sin^2 x = 4\] is


The number of solution in [0, π/2] of the equation \[\cos 3x \tan 5x = \sin 7x\] is 


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

sin4x = sin2x


Solve the following equations:
cot θ + cosec θ = `sqrt(3)`


Choose the correct alternative:
`(cos 6x + 6 cos 4x + 15cos x + 10)/(cos 5x + 5cs 3x + 10 cos x)` is equal to


Solve the equation sin θ + sin 3θ + sin 5θ = 0


Find the general solution of the equation sinx – 3sin2x + sin3x = cosx – 3cos2x + cos3x


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×