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Question
If A and B are such events that P(A) > 0 and P(B) ≠ 1, then P(A′|B′) equals ______.
Options
1 – P(A|B)
1– P(A′|B)
`(1 - "P"("A" ∪ "B"))/("P"("B'"))`
P(A′)|P(B′)
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Solution
If A and B are such events that P(A) > 0 and P(B) ≠ 1, then P(A′|B′) equals `(1 - "P"("A" ∪ "B"))/("P"("B'"))`.
Explanation:
Given that: P(A) > 0 and P(B) ≠ 1
∴ P(A′|B′) = `("P"("A'" ∩ "B'"))/("P"("B'"))`
= `(1 - "P"("A" ∪ "B"))/("P"("B'"))`
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