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Question
Let E and F be two independent events. The probability that both E and F happen is `1/12` and the probability that neither E nor F happens is `1/2`, then a value of `(P(E))/(P(F))` is ______.
Options
`4/3`
`3/2`
`1/3`
`5/12`
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Solution
Let E and F be two independent events. The probability that both E and F happen is `1/12` and the probability that neither E nor F happens is `1/2`, then a value of `(P(E))/(P(F))` is `bbunderline(4/3)`.
Explanation:
P(E∩F) = P(E). P(F) = `1/2`
P`(barE∩barF)=P(barE).P(barF) = 1/2`
(1 − P(E)) (1 − P(F)) = `1/2`
Let P(E) = x
P(F) = y
⇒ 1 − x − y + xy = `1/2` ⇒ 1 − x − y = `1/2 − 1/12 = 5/15`
⇒ x + y = `7/12 ⇒ x + 1/12x = 7/12` [∴ x.y = `1/12`]
12x2 − 7x + 1 = 0
12x2 − 4x − 3x + 1 = 0 = (4x − 1)(3x − 1) = 0
⇒ `x = 1/3, x = 1/4`
and y = `1/4, y = 1/3`
∴ `x/y = (1/3)/(1/4) = 4/3 or (1/4)/(1/3) = 3/4`
