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The probability that a student X solves a problem in dynamics is 25 and the probability that student Y solves the same problem is 14 . What is the probability that the problem is not solved

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Question

The probability that a student X solves a problem in dynamics is `2/5` and the probability that student Y solves the same problem is `1/4`. What is the probability that

  1. the problem is not solved
  2. the problem is solved
  3. the problem is solved exactly by one of them
Sum
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Solution

Let event A: Student X solves the problem in dynamics,

event B: Student Y solves the problem in dynamics.

∴ P(A) = `2/5`, P(B) = `1/4`

∴ P(A') = 1 – P(A) = `1 - 2/5 = 3/5`

P(B') = 1 – P(B) = `1 - 1/4 = 3/4`

A and B are independent events,

A' and B' are also independent events

(i) Let event C: Problem is not solved.

∴ P(C) = P(A' ∩ B')

= P(A') · P(B')

= `3/5 xx 3/4`

= `9/20`

(ii) Let event D: Problem is solved.

Problem can be solved if at least one of the two students solves the problem.

∴ P(C) = P(at least one student solves the problem)

= 1 - P (no student solves the problem)

= 1 - P(A' ∩ B')

= 1 - P (A') · P (B')

`= 1 - 3/5 xx 3/4`

`= 1 - 9/20`

`= 11/20`

(iii) Let event E: The problem is solved exactly by one of them.

∴ P(E) = P(A' ∩ B) ∪ P(A ∩ B')

= P(A') · P (B) + · P (A) · P (B')

`= (3/5 xx 1/4) + (2/5 xx 3/4)`

`= 3/20 + 6/20`

`= 9/20`

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Chapter 9: Probability - Exercise 9.3 [Page 206]

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