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Question
If 2, 6, p, 54 and q are in continued proportion, find the values of p and q.
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Solution
2, 6, p, 54 and q are in continued proportional then
⇒ `(2)/(6) = (6)/p = p/(54) = (54)/q`
(i) ∵ `(2)/(6) = (6)/p` then 2p = 36
⇒ p = 18
(ii) `p/(54) = (54)/q`
⇒ pq = 54 x 54
⇒ 18q = 54 x 54
⇒ q = `(54 xx 54)/(18)`
= 162
Hence p = 18, q = 162.
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