Advertisements
Advertisements
प्रश्न
If 2, 6, p, 54 and q are in continued proportion, find the values of p and q.
Advertisements
उत्तर
2, 6, p, 54 and q are in continued proportional then
⇒ `(2)/(6) = (6)/p = p/(54) = (54)/q`
(i) ∵ `(2)/(6) = (6)/p` then 2p = 36
⇒ p = 18
(ii) `p/(54) = (54)/q`
⇒ pq = 54 x 54
⇒ 18q = 54 x 54
⇒ q = `(54 xx 54)/(18)`
= 162
Hence p = 18, q = 162.
APPEARS IN
संबंधित प्रश्न
Find the third proportional to a – b and a2 – b2
Find the mean proportion of the following :
24 and 6
If q is the mean proportional between p and r, prove that
`p^2 - q^2 + r^2 = q^4[(1)/p^2 - (1)/q^2 + (1)/r^2]`.
Find the value of x in the following proportions : 10 : 35 = x : 42
Find the fourth proportional to 3, 12, 15
The weight of 65 books is 13 kg.
(i) What is the weight of 80 such books?
(ii) How many such books weigh 6.4 kg?
If `a/c = c/d = c/f` prove that : `(a^2)/(b^2) + (c^2)/(d^2) + (e^2)/(f^2) = "ac"/"bd" + "ce"/"df" + "ae"/"df"`
If a, b, c and d are in proportion, prove that: `(a + c)^3/(b + d)^3 = (a(a - c)^2)/(b(b - d)^2)`
If a, b, c, d are in continued proportion, prove that: `(a^3 + b^3 + c^3)/(b^3 + c^3 + d^3) = a/d`
The mean proportional between 4 and 9 is ______.
