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Question
If 0.2 mol of the following substance is required how many grams of that substance should be taken?
Calcium carbonate
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Solution
Molar mass of CaCO3 = 40 + 12 + 3(16) = 100 g/mol
Number of moles of a substance = `"Mass of the substance in grams"/"Molecular mass of the substance"`
Let Mass of the substance in grams be x,
`0.2 = "x"/100 = 20`g
we need, 20 g of CaCO3 for obtaining 0.2 moles of CaCO3.
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