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Question
Find the number of moles in 10 g of CaCO3.
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Solution
Molecular mass of CaCO3 = 40 + 12 + (16 × 3)
= 100 g
100 g of CaCO3 = 1 mole
∴ 10 g of CaCO3 = `1/100 xx 10`
= 0.1 mole
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