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Question
Given that the relative molecular mass of copper oxide is 80, what volume of ammonia (measured at STP) is required to completely reduce 120g of copper oxide? The equation for the reaction is :
3CuO + 2NH3 → 3Cu + 3H2O + N2
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Solution
3CuO + 2NH3 → 3Cu + 3H2O + N2
Molecular mass of CuO = 80
Volume occupied by 1 mole of NH3 = 22.4L
From the equation :
3 moles of CuO is reduced by 2 moles of ammonia
For 240g of CuO, volume of NH3 consumed = 44.8L
For 120g of CuO, volume of NH3 consumed
= 44.8 x 120 / 240 = 22.4 L
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