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Find the number of molecules in 73 g of HCl.

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Question

Find the number of molecules in 73 g of HCl.

Numerical
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Solution

HCl molecular mass = 1 + 35.5 = 36.5 g

36.5 g of HCl = 6.03 × 1023 molecules

∴ 73 g of molecules = `(6.03 xx 10^(23))/36.5 xx 73`

= 12.06 × 1023 

= 1.2 × 1024 

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5B [Page 84]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5B | Q 5. (a) | Page 84

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