English
Karnataka Board PUCPUC Science Class 11

Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them. HgClX2(aq)+2KI(aq)⟶HgIX2(s)+2KCl(aq) - Chemistry

Advertisements
Advertisements

Question

Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.

\[\ce{HgCl2 (aq) + 2KI (aq) -> HgI2 (s) + 2KCl (aq)}\]

Short/Brief Note
Advertisements

Solution

\[\ce{\overset{+2}{Hg}\overset{-1}{Cl2} (aq) + 2\overset{+1}{K}\overset{-1}{I} (aq) -> \overset{+2}{Hg}\overset{-1}{I2} (s) + 2\overset{+1}{K}\overset{-1}{Cl} (aq)}\]

Here O.N. of none of the atoms undergo a change and therefore, this is not a redox reaction.

shaalaa.com
Balancing Redox Reactions in Terms of Loss and Gain of Electrons
  Is there an error in this question or solution?
Chapter 8: Redox Reactions - Multiple Choice Questions (Type - I) [Page 108]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 11
Chapter 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 25.(ii) | Page 108

RELATED QUESTIONS

Consider the reaction:

\[\ce{O3(g) + H2O2(l) → H2O(l) + 2O2(g)}\]

Why it is more appropriate to write these reaction as:

\[\ce{O3(g) + H2O2 (l) → H2O(l) + O2(g) + O2(g)}\]

Also, suggest a technique to investigate the path of the redox reactions.


Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.


How do you count for the following observations?

Though alkaline potassium permanganate and acidic potassium permanganate both are used as oxidants, yet in the manufacture of benzoic acid from toluene we use alcoholic potassium permanganate as an oxidant. Why? Write a balanced redox equation for the reaction.


Balance the following equation in the basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent.

\[\ce{N2H4(l) + ClO^-_3 (aq) → NO(g) + Cl–(g)}\]


Chlorine is used to purify drinking water. Excess of chlorine is harmful. The excess of chlorine is removed by treating with sulphur dioxide. Present a balanced equation for this redox change taking place in water.


Justify that the following reaction is redox reaction; identify the species oxidized/reduced, which acts as an oxidant and which acts as a reductant.

\[\ce{2Cu2O_{(S)} + Cu2S_{(S)}->6Cu_{(S)} + SO2_{(g)}}\]


Balance the following redox equation by half-reaction method.

\[\ce{Bi(OH)_{3(s)} + SnO^2-_{2(aq)}->SnO^2-_{3(aq)} + Bi^_{(s)}(basic)}\]


Which of the following is INCORRECT for the following reaction?

\[\ce{2Zn_{(s)} + O2_{(g)} -> 2ZnO_{(s)}}\]


Identify coefficients 'x' and 'y' for the following reaction.

\[\ce{{x}H2O2_{(aq)} + ClO^-_{4(aq)} -> 2O2_{(g)} + ClO^-_{2(aq)} + {y}H2O_{(l)}}\]


Which of the following is a redox reaction?


Consider the reaction:

\[\ce{6 CO2(g) + 6H2O(l) → C6 H12O6(aq) + 6O2(g)}\]

Why it is more appropriate to write these reaction as:

\[\ce{6CO2(g) + 12H2O(l) → C6 H12O6(aq) + 6H2O(l) + 6O2(g)}\]

Also, suggest a technique to investigate the path of the redox reactions.


Write balanced chemical equation for the following reactions:

Reaction of liquid hydrazine \[\ce{(N2H4)}\] with chlorate ion \[\ce{(ClO^{-}3)}\] in basic medium produces nitric oxide gas and chloride ion in gaseous state.


Balance the following equations by the oxidation number method.

\[\ce{Fe^{2+} + H^{+} + Cr2O^{2-}7 -> Cr^{3+} + Fe^{3+} + H2O}\]


Balance the following equations by the oxidation number method.

\[\ce{MnO2 + C2O^{2-}4 -> Mn^{2+} + CO2}\]


Balance the following ionic equations.

\[\ce{MnO^{-}4 + SO^{2-}3 + H^{+} -> Mn^{2+} + SO^{2-}4 + H2O}\]


In acidic medium, reaction, \[\ce{MNO^-_4 → Mn^2+}\] an example of ____________.   


The weight of CO is required to form Re2(CO)10 will be ______ g, from 2.50 g of Re2O7 according to given reaction

\[\ce{Re2O7 + CO -> Re2(CO)10 + CO2}\]

Atomic weight of Re = 186.2; C = 12 and O = 16.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×