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Question
Balance the following equations by the oxidation number method.
\[\ce{I2 + NO^{-}3 -> NO2 + IO^{-}3}\]
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Solution
We can balance the given equation by oxidation number method-
Total decrease in O.N. = 1
To equilize O.N. multiply \[\ce{NO^{-}3}\], by 10
\[\ce{I2 + 10 NO^{-}3 -> 10NO2 + IO^{-}3}\]
Balancing atoms other than \[\ce{O}\] and \[\ce{H}\]
\[\ce{I2 + 10NO^{-}3 -> 10NO2 + 2IO^{-}3}\]
Balancing \[\ce{O}\] and \[\ce{H}\]
\[\ce{I2 + 10NO^{-}3 + 8H+ -> 10NO2 + 2IO^{-}3 + 4H2O}\]
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