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Karnataka Board PUCPUC Science Class 11

Write balanced chemical equation for the following reactions: Dichlorine heptaoxide (ClX2OX7) in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorit

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Question

Write balanced chemical equation for the following reactions:

Dichlorine heptaoxide \[\ce{(Cl2O7)}\] in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion \[\ce{(ClO^{-}2)}\] and oxygen gas. (Balance by ion-electron method)

Short/Brief Note
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Solution

\[\ce{Cl2O7 (g) + 4H2O2 (aq) -> 2ClO^{-}2 (aq) + 3H2O (l) + 4O2 (g) + 2H+ (aq)}\]

Balancing by ion-electron method:

Oxidation half: \[\ce{H2O2 -> O2 + 2e-}\]

Adding \[\ce{2H+}\] on right side to balance H atoms and charge.

\[\ce{H2O2 -> O2 + 2H^{+} + 2e-}\]

Reduction half: \[\ce{Cl2O7 + 8e- -> 2ClO^{-}2}\]

Adding \[\ce{H2O}\] and \[\ce{H+}\] to balance \[\ce{H}\] and \[\ce{O}\] atoms

\[\ce{Cl2O7 + 8e- + 6H+ -> 2ClO^{-}2 + 3H2O}\]

Adding oxidation and reduction half

\[\ce{[H2O2 -> O2 + 2e- + 2H+] × 4}\]

\[\ce{Cl2O7 + 8e- + 6H+ -> 2ClO^{-}2 + 3H2O}\]
                                                                                                 

\[\ce{Cl2O7 + 4H2O2 -> 2ClO^{-}2 + 3H2O + 4O2 + 2H+}\]

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Chapter 8: Redox Reactions - Multiple Choice Questions (Type - I) [Page 108]

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NCERT Exemplar Chemistry Exemplar [English] Class 11
Chapter 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 21.(iii) | Page 108

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