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Question
Balance the following equations by the oxidation number method.
\[\ce{MnO2 + C2O^{2-}4 -> Mn^{2+} + CO2}\]
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Solution
We can balance the given equation by oxidation number method-
\[\ce{\overset{+4}{Mn}O2 + \overset{+3}{C2}O^{2-}4 -> M\overset{+2}{n^{2+}} + C\overset{+4}{O2}}\]
The balanced chemical reaction is given as-
Total increase in O.N. = 5 × 2 = 10
To equilize O.N. multiply \[\ce{CO2}\] by 2.
\[\ce{MnO2 + C2O^{2-}4 -> Mn^{2+} + CO2}\]
Balance \[\ce{H}\] and \[\ce{O}\] by adding \[\ce{2H2O}\] on right side, and \[\ce{4H+}\] on left side of equation.
\[\ce{MnO2 + C2O^{2-}4 + 4H+ -> Mn^{2+} + 2CO2 + 2H2O}\]
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