Advertisements
Advertisements
Question
A uniform meter scale is in equilibrium as shown in the diagram :

(i) Calculate the weight of the meter scale.
(ii) Which of the following options is correct to keep the ruler in equilibrium when 40 gf wt is shifted to 0 cm mark ?
F is shifted towards 0 cm
or
F is shifted towards 100 cm
Advertisements
Solution

(i) Mass of the meter scale wiil be concentrated at its centre
∴ At 50 cm, Mass of meter scale = M gf
`therefore F_1d_1= F_2 d_2`
`(25) = F_2(20)`
50 gf = F2
0.49N = F2
∴ F2 = m (9.8)
`=(0.49)/(9.8)= m`
∴ m = 0.05kg
1m = 500m
(ii) F is shifted towards 0 cm.
APPEARS IN
RELATED QUESTIONS
Define equilibrium.
State the condition when a body is in dynamic equilibrium.
The figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40 gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
- Is the metre rule in equilibrium? If not how will the rule turn?
- How can the rule be brought in equilibrium by using an additional weight of 40 gf?

State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.

A meter scale is pivoted at its mid point and a 50 g mass suspended from the 20 cm mark. What mass balances the ruler when suspended from 65 cm mark?
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
Explain when we carry weight, on one hand, we bend on the other side.
Explain the types of stability with suitable examples.
Explain the concept which is used in the continuous movement of the Thanjavur doll?
Give one example of dynamic equilibrium.
