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प्रश्न
A uniform meter scale is in equilibrium as shown in the diagram :
(i) Calculate the weight of the meter scale.
(ii) Which of the following options is correct to keep the ruler in equilibrium when 40 gf wt is shifted to 0 cm mark ?
F is shifted towards 0 cm
or
F is shifted towards 100 cm
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उत्तर
(i) Mass of the meter scale wiil be concentrated at its centre
∴ At 50 cm, Mass of meter scale = M gf
`therefore F_1d_1= F_2 d_2`
`(25) = F_2(20)`
50 gf = F2
0.49N = F2
∴ F2 = m (9.8)
`=(0.49)/(9.8)= m`
∴ m = 0.05kg
1m = 500m
(ii) F is shifted towards 0 cm.
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संबंधित प्रश्न
State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.
State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.
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State the principle of moments.
Define the term momentum.
State two conditions when the work done by a force acting on a body is zero.
What is meant by equilibrium and state the conditions of equilibrium of a body?
How can we increase the stability of an object?
