Advertisements
Advertisements
प्रश्न
A uniform meter scale is in equilibrium as shown in the diagram :
(i) Calculate the weight of the meter scale.
(ii) Which of the following options is correct to keep the ruler in equilibrium when 40 gf wt is shifted to 0 cm mark ?
F is shifted towards 0 cm
or
F is shifted towards 100 cm
Advertisements
उत्तर
(i) Mass of the meter scale wiil be concentrated at its centre
∴ At 50 cm, Mass of meter scale = M gf
`therefore F_1d_1= F_2 d_2`
`(25) = F_2(20)`
50 gf = F2
0.49N = F2
∴ F2 = m (9.8)
`=(0.49)/(9.8)= m`
∴ m = 0.05kg
1m = 500m
(ii) F is shifted towards 0 cm.
APPEARS IN
संबंधित प्रश्न
In a beam balance, when the beam is balanced in a horizontal position, it is in ______ equilibrium.
State the principle of moments. Give one device as an application of it
The figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40 gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
- Is the metre rule in equilibrium? If not how will the rule turn?
- How can the rule be brought in equilibrium by using an additional weight of 40 gf?
Give scientific reason for the following:
When a man climbs a slope he bends forward.
In equilibrium algebraic sum of moments of all forces about the point of rotation is ______.
Explain why It is easier to knock down a boy who is standing on one foot than one who is standing on two.
What is the weight of a body placed at the centre of the earth?
What is meant by equilibrium?
A boy of mass 30 kg is fitting at a distance of 2 m from the middle of a see-saw. Where should a boy of mass 40 kg sit so as to balance the see-saw?
Explain the concept which is used in the continuous movement of the Thanjavur doll?
