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Question
How will you convert ethyl chloride into n – butane?
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Solution
\[\ce{\underset{\text{}Ethyl chloride}{C2H5Cl + 2Na +}Cl - C2H5 ->[-2NaBr][dry ether] CH3 - \underset{\text{n - butane}}{CH2 - CH2 - CH3}}\]
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\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
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